If the radius of the octaheral void is `r` and the radius of the atoms in close-packing is `R`, derive relation between `r` and `R`

(a) If the radius of octahedral void is 'r' and the radius of the atoms in close packing is 'R' what is the relation between 'r' and 'R' ? (b) A metal crystallises in body centred cubic structure. If 'a' is the edge length of its unit cell, 'r' is the radius of the sphere, what is the relation between 'r' and 'a' ?

If the radius of a tetrahedral void is 'r' and radius of atom in close packing is 'R', derive the relation between r and R.

If the radius of the octahedral void is r and radius of the atom in closet packed structure is R then

If R is the radius of the octahedral voids and r is the radius of the atom in close packing, then r//R is equal to

If radius of an octahedral void is r and atomic radius of atoms assuming cubical close pacting is R. Then the relation between r and R is

The radius of an octahedral void is 'r' and the radius of an atom is 'R' when these are in close packing. Derive the relation between the two.

If r is the radius of first orbit, the radius of nth orbit of the H atom will be:

If r is radius of first orbit , the radius of nth orbit of the H atom will be

If r is radius of first orbit , the radius of nth orbit of the H atom will be

If the radius of the spheres in the close packing is R and the radius pf pctahedral voids is r , then r = 0.414R .