why is ` Fe0(s)` not formed in stoichiometric compostion ?

Explanation

To understand why FeO (ferrous oxide) is not formed in a stoichiometric composition, we need to analyze the oxidation states of iron and the structure of the compound. Here’s a step-by-step solution:

### Step 1: Understanding the Composition of FeO
FeO is expected to have a 1:1 ratio of iron (Fe) to oxygen (O) in its stoichiometric form, where iron exists in the +2 oxidation state (Fe²⁺) and oxygen in the -2 oxidation state (O²⁻).

### Step 2: Oxidation States of Iron
In ferrous oxide (FeO), iron can exist in two oxidation states: +2 (Fe²⁺) and +3 (Fe³⁺). The presence of Fe³⁺ ions in the crystal structure leads to a deviation from the expected stoichiometric composition.

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