Home
Class 12
CHEMISTRY
The melting points RbBr is 682^(@)C, whi...

The melting points RbBr is `682^(@)C`, while that of NaF is `988^(@)`. The principal reason of this fact is :

Text Solution

Verified by Experts

Both are crystalline solids and the melting points are directly linked to the respective lattice energies. Now, the magnitude of lattice energy is directly proporational to charge on ions and inversely to the interionic distance. In the above case both the cation shave +1 unit charge while anions have -1 unit charge. Since `Br^(-)` ions is bigger than `F^(-)` ion, the lattice energy for NaF crystals is more and therefore, the melting point is higher than of RbBr crystals.
Promotional Banner

Similar Questions

Explore conceptually related problems

The melting point of RbBr is 682^(@)C , while that of NaF is 988^(@)C . The principla reason that melting point of NaF is much higher than that of RbBr is that :

The melting point of RbBr is 682^(@)C , while that of NaF is 988^(@)C . The principle reason that melting point of NaF is much higher than that of RbBr is that :

Which have melting point below 500^(@)C

The melting point of gold is 1064^(@)C . Express this in ""^(@)F and K.

The melting point of AlF_(3) is 104^(@) C and that of SiF_(4) is -77^(@) C (it sublimes) because:

A metal with melting point less than 50^(@)C is

Why do the melting points decrease in going from NaF to Nal?

A solid metal weighing 150 g melts at its melting point of 800^(@)C by providing heat at the rate of 100 W. The time taken for it to completely melt at the same temperature is 4 min. What is the specific latent heat of fusion of the metal ?

.Which of the following statements is true: (a) Melting point of Phosphorous is less than that of Nitrogen (b) N_(2) is highly reactive while P_(4) is inert (c) Nitrogen shows higher tendency of catenation than P (d)N-N is weaker than P-P