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The percentage of empty space in a simpl...

The percentage of empty space in a simple cubic arrangement is :

A

74

B

68

C

32

D

48

Text Solution

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The correct Answer is:
To find the percentage of empty space in a simple cubic arrangement, we will follow these steps: ### Step 1: Understand the Simple Cubic Unit Cell A simple cubic unit cell consists of atoms located only at the corners of a cube. Each corner atom contributes 1/8th of its volume to the unit cell. ### Step 2: Determine the Number of Atoms in the Unit Cell In a simple cubic structure, there are 8 corner atoms. The contribution of these atoms to the unit cell is: \[ \text{Total atoms} = 8 \times \frac{1}{8} = 1 \] Thus, the number of atoms per unit cell (Z) is 1. ### Step 3: Calculate the Edge Length Let the radius of the atom be \( r \). In a simple cubic arrangement, the edge length \( a \) of the cube is given by: \[ a = 2r \] ### Step 4: Calculate the Volume of the Sphere The volume \( V \) of a single atom (considered as a sphere) is given by the formula: \[ V = \frac{4}{3} \pi r^3 \] ### Step 5: Calculate the Volume of the Cube The volume of the cube is given by: \[ \text{Volume of cube} = a^3 = (2r)^3 = 8r^3 \] ### Step 6: Calculate the Packing Fraction The packing fraction (PF) is the ratio of the volume occupied by the atoms to the volume of the unit cell: \[ \text{Packing Fraction} = \frac{\text{Volume of atoms}}{\text{Volume of cube}} = \frac{\frac{4}{3} \pi r^3}{8r^3} \] Simplifying this gives: \[ \text{Packing Fraction} = \frac{4\pi}{24} = \frac{\pi}{6} \] Calculating this numerically: \[ \text{Packing Fraction} \approx 0.524 \] ### Step 7: Calculate Packing Efficiency The packing efficiency is given by: \[ \text{Packing Efficiency} = \text{Packing Fraction} \times 100 \approx 52.4\% \] ### Step 8: Calculate the Percentage of Empty Space The percentage of empty space (voids) in the unit cell is calculated as: \[ \text{Percentage of voids} = 100 - \text{Packing Efficiency} \] Substituting the values: \[ \text{Percentage of voids} = 100 - 52.4 = 47.6\% \] This can be approximated to: \[ \text{Percentage of voids} \approx 48\% \] ### Conclusion Thus, the percentage of empty space in a simple cubic arrangement is approximately **48%**. ---
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