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The Ca^(2+) and F^(-) ions arc located i...

The `Ca^(2+)` and `F^(-)` ions arc located in `CaF_(2)` crystal respectively at what position ? What is the charge ratio ?

A

FCC lattice , tetrahedral voids , 2 : 1

B

FCC lattice , half of tetrahedral voids , 1 : 2

C

BCC lattice , octahedral voids , 2 : 1

D

FCC lattice , half of octahedral voids , 1 : 2

Text Solution

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The correct Answer is:
To solve the question regarding the positions of `Ca^(2+)` and `F^(-)` ions in the `CaF2` crystal and the charge ratio, we can follow these steps: ### Step 1: Identify the Structure of `CaF2` `CaF2` is an ionic compound composed of calcium ions (`Ca^(2+)`) and fluoride ions (`F^(-)`). The structure of `CaF2` can be understood by recognizing that it forms a face-centered cubic (FCC) lattice. **Hint:** Remember that in ionic compounds, cations and anions arrange themselves in a way that minimizes repulsion and maximizes attraction. ### Step 2: Determine the Positions of `Ca^(2+)` and `F^(-)` Ions In the `CaF2` crystal structure: - The `Ca^(2+)` ions occupy the lattice points of the FCC structure. - The `F^(-)` ions occupy the tetrahedral voids in the FCC lattice. **Hint:** The size of the ions influences their positions; larger cations typically occupy lattice points, while smaller anions occupy voids. ### Step 3: Understand the Coordination Numbers - The coordination number of the `Ca^(2+)` ion in the FCC lattice is 8. - The coordination number of the `F^(-)` ion in the tetrahedral void is 4. **Hint:** Coordination number refers to the number of nearest neighbors surrounding an ion in the lattice. ### Step 4: Calculate the Charge Ratio The charge of `Ca^(2+)` is +2 and the charge of `F^(-)` is -1. The charge ratio can be expressed as: - Charge ratio = Charge of `Ca^(2+)` : Charge of `F^(-)` = 2 : 1 **Hint:** The charge ratio reflects the stoichiometry of the compound; it indicates how many anions are needed to balance the charge of the cations. ### Step 5: Summarize the Findings - Positions: `Ca^(2+)` ions are at the FCC lattice points, and `F^(-)` ions are in the tetrahedral voids. - Charge Ratio: The charge ratio is 2:1. **Final Answer:** - Positions: `Ca^(2+)` at FCC lattice points, `F^(-)` in tetrahedral voids. - Charge Ratio: 2:1.

To solve the question regarding the positions of `Ca^(2+)` and `F^(-)` ions in the `CaF2` crystal and the charge ratio, we can follow these steps: ### Step 1: Identify the Structure of `CaF2` `CaF2` is an ionic compound composed of calcium ions (`Ca^(2+)`) and fluoride ions (`F^(-)`). The structure of `CaF2` can be understood by recognizing that it forms a face-centered cubic (FCC) lattice. **Hint:** Remember that in ionic compounds, cations and anions arrange themselves in a way that minimizes repulsion and maximizes attraction. ### Step 2: Determine the Positions of `Ca^(2+)` and `F^(-)` Ions ...
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