A solid solution of `CdBr_(2)` in AgBr contains

Options

A. Schottky defects
B. Frenkel defects
C. Colour Centres
D. Frenkel as well as Schottky defects

Answer

To solve the question regarding the solid solution of `CdBr_(2)` in `AgBr`, we need to analyze the types of defects that can occur in ionic solids and how they relate to the sizes of the ions involved.

### Step-by-Step Solution:

1. **Understanding Ionic Solids**:
- Ionic solids are composed of cations and anions held together by electrostatic forces. The arrangement of these ions can be affected by defects, which can influence the properties of the solid.

**Hint**: Recall that ionic solids consist of positively charged cations and negatively charged anions.

2. **Identifying the Ions**:
- In this case, we have `CdBr_(2)` which consists of `Cd^(2+)` cations and `Br^(-)` anions, and `AgBr` which consists of `Ag^(+)` cations and `Br^(-)` anions.

**Hint**: Write down the charges of the ions in both compounds to understand their interactions.

3. **Comparing Ionic Sizes**:
- The size of the cations and anions plays a crucial role in determining the type of defects that can occur. `Cd^(2+)` is larger than `Ag^(+)`, and both `Br^(-)` ions are the same in size.

**Hint**: Compare the ionic radii of `Cd^(2+)` and `Ag^(+)` to see how they relate to each other.

4. **Types of Defects**:
- **Frenkel Defect**: This defect occurs when a smaller ion is displaced from its normal lattice position to an interstitial site. This is common when there is a significant size difference between the ions.
- **Schottky Defect**: This defect occurs when an equal number of cations and anions are missing from the lattice, creating vacancies. This is common when the cations and anions are of similar sizes.

**Hint**: Recall the definitions of Frenkel and Schottky defects and when they occur.

5. **Application to the Given Compounds**:
- In the solid solution of `CdBr_(2)` in `AgBr`, both Frenkel and Schottky defects can occur. The presence of `Cd^(2+)` can lead to Frenkel defects due to its larger size compared to `Ag^(+)`, while Schottky defects can occur due to the similar sizes of `Ag^+` and `Br^-`.

**Hint**: Consider how the presence of different ions affects the arrangement and defects in the crystal lattice.

6. **Conclusion**:
- Therefore, the solid solution of `CdBr_(2)` in `AgBr` contains both Frenkel and Schottky defects due to the size differences and the nature of the ionic compounds involved.

**Hint**: Summarize the types of defects identified and how they relate to the ionic sizes.

### Final Answer:
The solid solution of `CdBr_(2)` in `AgBr` contains both Frenkel and Schottky defects.