Home
Class 12
CHEMISTRY
Assertion: Diamond has a ccp arrangement...

Assertion: Diamond has a ccp arrangement in which corners, face centres and alternate tetrahedral holes are occupied by C atoms
Reason: In diamond, C atoms at corners are `sp^(3)` hybridised but at the face centres these are `sp^(2)` hybridised

A

If both assertion and reason are correct and reason is correct explanation for assertion

B

If both assertion and reason are correct but reason is not correct explanation for assertion

C

If assertion is correct but reason is incorrect

D

If both assertion and reason are incorrect

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given question, we need to analyze both the assertion and the reason provided. ### Step 1: Understand the Assertion The assertion states that diamond has a CCP (cubic close packing) arrangement where corners, face centers, and alternate tetrahedral holes are occupied by carbon atoms. - **CCP Arrangement**: In a cubic close-packed structure, the atoms are arranged in a way that maximizes packing efficiency. In the case of diamond, it can be visualized as a face-centered cubic (FCC) lattice with additional carbon atoms occupying the tetrahedral voids. ### Step 2: Analyze the Carbon Atom Positions In diamond: - Carbon atoms occupy the corners and face centers of the unit cell. - Additionally, carbon atoms occupy half of the tetrahedral voids. ### Step 3: Determine the Hybridization of Carbon Atoms The reason states that: - Carbon atoms at the corners are `sp^3` hybridized. - Carbon atoms at the face centers are `sp^2` hybridized. - **Hybridization in Diamond**: In diamond, all carbon atoms are actually `sp^3` hybridized. This hybridization leads to a tetrahedral geometry, which is characteristic of diamond's structure. ### Step 4: Conclusion on Assertion and Reason - The assertion is correct: Diamond does have a CCP arrangement with carbon atoms occupying specific positions. - The reason is incorrect: All carbon atoms in diamond are `sp^3` hybridized, not `sp^2` at the face centers. ### Final Answer Thus, the conclusion is: - The assertion is correct, but the reason is incorrect. ### Correct Option The correct option is that the assertion is correct but the reason is incorrect. ---

To solve the given question, we need to analyze both the assertion and the reason provided. ### Step 1: Understand the Assertion The assertion states that diamond has a CCP (cubic close packing) arrangement where corners, face centers, and alternate tetrahedral holes are occupied by carbon atoms. - **CCP Arrangement**: In a cubic close-packed structure, the atoms are arranged in a way that maximizes packing efficiency. In the case of diamond, it can be visualized as a face-centered cubic (FCC) lattice with additional carbon atoms occupying the tetrahedral voids. ### Step 2: Analyze the Carbon Atom Positions ...
Promotional Banner

Similar Questions

Explore conceptually related problems

Assertion:Face centred cubic cell has 4 atoms per unit cell. Reason:In fcc unit cell , there are 8 atoms at the corners and 6 atoms at face centres .

In a cubic unit cell, seven of the eight corners are occupied by atoms A and centres of faces are occupied by atoms B. The general formula of the compound is:

In which of the following compounds B atoms are in sp^(2) and sp^(3) hybridisation states ?

Assertion: Alkanes containing more than three carbon atoms exhibit chain isomerism. Reason: In an alkane, all carbon atoms are sp^(3) hybridised.

Consider the given statement about the molecule 1. Three carbon atoms are sp^(3) - hybridised 2. Three carbon atoms are sp^(2)- hybridised 3. Two carbon atoms are sp - hybridised

In fcc lattice ,A, B, C,D atoms are arranged at corner , face centre , ocatahedral void and tetrahedral void respectively , then the body diagonal contains :

Among the following compounds, which has three sp-hybridised carbon atoms ?

Assertion (A) : CO_2 is linear Reason (R) : C is not in sp- hybridised state .

Atoms A, B, C and D are present at corners, face centres, body centres and edge centres and respectively in a cubic unit cell. Find the formula of compound.