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If the unit cell of a mineral has cubic ...

If the unit cell of a mineral has cubic close packed (ccp) array of oxygen atoms with m fraction of octahedral holes occupied by aluminium ions and n fraction of tetrahedral holes occupied by magnesiums ions, m and n respectively, are

A

`1/2, 1/8`

B

`1, 1/4`

C

`1/2, 1/2`

D

`1/4, 1/8`

Text Solution

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To solve the problem, we need to analyze the cubic close-packed (ccp) structure of oxygen atoms and determine the fractions of octahedral and tetrahedral holes occupied by aluminum and magnesium ions, respectively. ### Step-by-Step Solution: 1. **Understanding the CCP Structure**: - In a cubic close-packed (ccp) structure, which is equivalent to face-centered cubic (FCC), oxygen ions are arranged at the corners and face centers of the cube. - Each unit cell of ccp contains 4 oxygen ions. 2. **Identifying the Types of Holes**: - In a ccp structure, there are two types of voids: octahedral and tetrahedral. - The total number of octahedral voids in a ccp unit cell is 4. - The total number of tetrahedral voids in a ccp unit cell is 8. 3. **Occupancy of Octahedral Holes**: - The problem states that a fraction \( m \) of the octahedral holes is occupied by aluminum ions (Al³⁺). - Since there are 4 octahedral voids, if \( m \) fraction is occupied, then the number of octahedral holes occupied by aluminum is \( 4m \). - Given that aluminum is a trivalent cation (Al³⁺), it occupies half of the octahedral voids. Therefore, \( m = \frac{1}{2} \). 4. **Occupancy of Tetrahedral Holes**: - The problem states that a fraction \( n \) of the tetrahedral holes is occupied by magnesium ions (Mg²⁺). - Since there are 8 tetrahedral voids, if \( n \) fraction is occupied, then the number of tetrahedral holes occupied by magnesium is \( 8n \). - Given that magnesium is a divalent cation (Mg²⁺), it occupies one of the tetrahedral voids. Therefore, \( n = \frac{1}{8} \). 5. **Final Values**: - From the above analysis, we find: - \( m = \frac{1}{2} \) - \( n = \frac{1}{8} \) ### Conclusion: Thus, the fractions of octahedral and tetrahedral holes occupied by aluminum and magnesium ions are: - \( m = \frac{1}{2} \) - \( n = \frac{1}{8} \)

To solve the problem, we need to analyze the cubic close-packed (ccp) structure of oxygen atoms and determine the fractions of octahedral and tetrahedral holes occupied by aluminum and magnesium ions, respectively. ### Step-by-Step Solution: 1. **Understanding the CCP Structure**: - In a cubic close-packed (ccp) structure, which is equivalent to face-centered cubic (FCC), oxygen ions are arranged at the corners and face centers of the cube. - Each unit cell of ccp contains 4 oxygen ions. ...
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A spinel is an important class of oxide consisting two types of metal ions with the oxide ions arranged in ccp layers . The normal spinel has one -eight of the tetrahedral holes occupied by one type of metal ions and one- half of the octaherdral holes occupied by another type of metal ion. Such a spine is formed by Mg^(2+), Al^(3+) and O^(2-) . The neutrality of the crystal is being maintained. Type of hole occupied by Mg^(2+) ions is: