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Which isomerism is shown by the followin...

Which isomerism is shown by the following pairs ?
`CH_(3)CH_(2)CH_(2)OH and CH_(3)CH_(2)OCH_(3)`

A

Position isomerism

B

Functional isomerism

C

Structural isomerism

D

Chain isomerism.

Text Solution

AI Generated Solution

The correct Answer is:
To determine the type of isomerism shown by the compounds CH₃CH₂CH₂OH (propan-1-ol) and CH₃CH₂OCH₃ (methoxypropane), we can follow these steps: ### Step 1: Identify the Compounds - The first compound, CH₃CH₂CH₂OH, is an alcohol due to the presence of the hydroxyl (-OH) group. - The second compound, CH₃CH₂OCH₃, is an ether because it contains an ether functional group (-O-). ### Step 2: Analyze the Functional Groups - The presence of different functional groups (alcohol and ether) indicates that these compounds belong to different classes of organic compounds. ### Step 3: Determine the Type of Isomerism - Since the two compounds have the same molecular formula (C₄H₁₀O) but differ in their functional groups, they exhibit functional isomerism. ### Step 4: Conclusion - Therefore, the type of isomerism shown by the pair CH₃CH₂CH₂OH and CH₃CH₂OCH₃ is **functional isomerism**. ### Final Answer The isomerism shown by the pairs CH₃CH₂CH₂OH and CH₃CH₂OCH₃ is **functional isomerism**. ---
To determine the type of isomerism shown by the compounds CH₃CH₂CH₂OH (propan-1-ol) and CH₃CH₂OCH₃ (methoxypropane), we can follow these steps: ### Step 1: Identify the Compounds - The first compound, CH₃CH₂CH₂OH, is an alcohol due to the presence of the hydroxyl (-OH) group. - The second compound, CH₃CH₂OCH₃, is an ether because it contains an ether functional group (-O-). ### Step 2: Analyze the Functional Groups - The presence of different functional groups (alcohol and ether) indicates that these compounds belong to different classes of organic compounds. ...
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