Among the following ethers, which one will produce methyl alcohol on treatment with hot concentrated `HI`?

Options

A. `CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)-O-CH_(3)`
B. `CH_(3)-CH_(2)-CH_(2)-CH_(2)-O-CH_(3)`
C. `CH_(3)-CH_(2)-underset(CH_(3))underset(|)(CH)-O-CH_(3)`
D. `CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-OCH_(3)`

Explanation

To determine which ether will produce methyl alcohol (methanol) upon treatment with hot concentrated HI, we need to analyze the ethers given in the options.

### Step-by-Step Solution:

1. **Identify the ethers**: We have four ethers to consider. Let's denote them as:
- Option 1: CH3CH(CH3)CH2OCH3
- Option 2: CH3CH2CH2OCH3
- Option 3: CH3CH2CH(CH3)OCH3
- Option 4: (CH3)2C(CH3)OCH3

2. **Understand the reaction with HI**: Ethers react with hydrogen iodide (HI) to produce alcohols and alkyl iodides. The reaction typically involves cleavage of the ether bond (C-O) and formation of an alcohol and an alkyl halide.

3. **Analyze each ether**:
- **Option 1**: CH3CH(CH3)CH2OCH3
- Upon reaction with HI, it can produce CH3OH (methyl alcohol) and CH3I (methyl iodide).
- **Option 2**: CH3CH2CH2OCH3
- This will produce CH3OH and CH3CH2CH2I (propyl iodide).
- **Option 3**: CH3CH2CH(CH3)OCH3
- This will produce CH3OH and CH3CH(CH3)I (isopropyl iodide).
- **Option 4**: (CH3)2C(CH3)OCH3
- This will produce CH3OH and (CH3)2C(CH3)I (tert-butyl iodide).

4. **Determine which option produces methyl alcohol**:
- From the analysis, **Option 1** is the only ether that directly produces methyl alcohol (CH3OH) upon reaction with HI.

5. **Conclusion**: Therefore, the ether that will produce methyl alcohol on treatment with hot concentrated HI is **Option 1**: CH3CH(CH3)CH2OCH3.

### Final Answer:
**Option 1: CH3CH(CH3)CH2OCH3 produces methyl alcohol on treatment with hot concentrated HI.**