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The compound A on treatment with Na give...

The compound `A` on treatment with `Na` gives `B`, and with `PCl_(5)` gives `C`. `B` and `C` react together to give di Ethyl ether. `A,B` and `C` are in the order

A

`C_(2)H_(5)OH,C_(2)H_(6),C_(2)H_(5)CI`

B

`C_(2)H_(5)OH,C_(2)H_(5)CI,C_(2)H_(5)OH`

C

`C_(2)H_(5)CI,C_(2)H_(6),C_(2)H_(5)OH`

D

`C_(2)H_(5)OH,C_(2)H_(5)O Na,C_(2)H_(5)CI`

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To solve the problem step by step, let's analyze the information given and deduce the compounds A, B, and C. ### Step 1: Identify Compound A The problem states that compound A reacts with sodium (Na) to form compound B. In organic chemistry, when alcohols react with sodium, they form sodium alkoxides. Given that the final product is diethyl ether, we can deduce that compound A is likely an alcohol. **Conclusion:** Compound A is Ethanol (C₂H₅OH). ### Step 2: Determine Compound B When ethanol (C₂H₅OH) reacts with sodium (Na), it forms sodium ethoxide (C₂H₅ONa) and hydrogen gas (H₂) as a byproduct. **Reaction:** \[ \text{C₂H₅OH} + \text{Na} \rightarrow \text{C₂H₅ONa} + \frac{1}{2} \text{H₂} \] **Conclusion:** Compound B is Sodium Ethoxide (C₂H₅ONa). ### Step 3: Identify Compound C The problem states that compound A also reacts with phosphorus pentachloride (PCl₅) to form compound C. Alcohols react with PCl₅ to form alkyl chlorides. Therefore, ethanol (C₂H₅OH) will react with PCl₅ to form chloroethane (C₂H₅Cl). **Reaction:** \[ \text{C₂H₅OH} + \text{PCl₅} \rightarrow \text{C₂H₅Cl} + \text{POCl₃} + \text{HCl} \] **Conclusion:** Compound C is Chloroethane (C₂H₅Cl). ### Step 4: Reaction of B and C Now, we need to see how compounds B and C react together to form diethyl ether. Sodium ethoxide (C₂H₅ONa) reacts with chloroethane (C₂H₅Cl) to form diethyl ether (C₂H₅O-C₂H₅) and sodium chloride (NaCl) as a byproduct. **Reaction:** \[ \text{C₂H₅ONa} + \text{C₂H₅Cl} \rightarrow \text{C₂H₅O-C₂H₅} + \text{NaCl} \] **Conclusion:** The reaction confirms that diethyl ether is formed from the reaction of B and C. ### Final Summary - **Compound A:** Ethanol (C₂H₅OH) - **Compound B:** Sodium Ethoxide (C₂H₅ONa) - **Compound C:** Chloroethane (C₂H₅Cl) Thus, the order of compounds A, B, and C is: - A = C₂H₅OH (Ethanol) - B = C₂H₅ONa (Sodium Ethoxide) - C = C₂H₅Cl (Chloroethane)
To solve the problem step by step, let's analyze the information given and deduce the compounds A, B, and C. ### Step 1: Identify Compound A The problem states that compound A reacts with sodium (Na) to form compound B. In organic chemistry, when alcohols react with sodium, they form sodium alkoxides. Given that the final product is diethyl ether, we can deduce that compound A is likely an alcohol. **Conclusion:** Compound A is Ethanol (C₂H₅OH). ...
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