`CH_(3)-overset(CH_(2)CH_(3))overset(|)(CH)CH=CHCH_(3)overset(H_(3)O^(+))rarr`
find the product of the reaction .

Explanation

To solve the given reaction step by step, we will analyze the hydrolysis of the alkene provided in the question.

### Step 1: Identify the Alkene
The compound given is:
\[ CH_3-CH(CH_2CH_3)-CH=CH-CH_3 \]
This structure indicates that we have an alkene due to the presence of a double bond (C=C).

### Step 2: Hydrolysis of the Alkene
When an alkene undergoes hydrolysis in the presence of an acid (H₃O⁺), it typically results in the formation of an alcohol. The reaction involves the addition of H⁺ (proton) and OH⁻ (hydroxide ion) across the double bond.

### Step 3: Formation of Carbocation
The double bond will break, leading to the formation of a carbocation. The most stable carbocation will form, which is typically a secondary or tertiary carbocation. In this case, we can visualize the following:
- The double bond opens, and one carbon will carry a positive charge (carbocation) while the other will carry a negative charge.

### Step 4: Rearrangement of Carbocation
If the initial carbocation formed is not the most stable, it may undergo rearrangement. In this case, we will have a hydride shift, where a hydrogen atom from a neighboring carbon shifts to stabilize the carbocation, resulting in a more stable tertiary carbocation.

### Step 5: Nucleophilic Attack by OH⁻
Once the stable carbocation is formed, the hydroxide ion (OH⁻) will attack the positively charged carbon, leading to the formation of the alcohol.

### Step 6: Final Product
The final product of the reaction will be an alcohol. The structure of the alcohol can be represented as:
\[ CH_3-CH(CH_2CH_3)-CH(OH)-CH_2-CH_3 \]
This compound has a chiral center due to the presence of four different groups attached to one of the carbon atoms, making it optically active.

### Conclusion
The major product of the reaction is:
\[ CH_3-CH(CH_2CH_3)-CH(OH)-CH_2-CH_3 \]
This is an alcohol and is optically active due to the chiral carbon.

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