Ethy`-`tert-buty' ether on heating with `HI` of one molar concentration gives

Options

A. `C_(2)H_(5)OH+(CH_(3))_(3)C CI`
B. `C_(2)H_(5)I+(CH_(3))_(3)COH`
C. `C_(2)H_(5)I+(CH_(3))_(3)C CI`
D. None of these

Explanation

To solve the question regarding the reaction of ethyl-tert-butyl ether with HI, we will follow these steps:

### Step 1: Identify the Structure of Ethyl-tert-butyl Ether
- Ethyl-tert-butyl ether consists of an ethyl group (C2H5) and a tert-butyl group (C(CH3)3) connected by an oxygen atom.
- The structure can be represented as:
```
CH3
|
CH3 - C - O - CH2 - CH3
|
CH3
```

### Step 2: Understand the Reaction with HI
- When ethyl-tert-butyl ether is heated with HI (hydroiodic acid), the ether undergoes protonation.
- The oxygen atom in the ether has lone pairs that can attract the hydrogen from HI, forming an oxonium ion.

### Step 3: Formation of the Oxonium Ion
- The reaction can be illustrated as:
```
C(CH3)3 - O - CH2 - CH3 + H+ → C(CH3)3 - O^+H - CH2 - CH3
```
- This results in the formation of an oxonium ion where the oxygen carries a positive charge.

### Step 4: Mechanism of Reaction
- The reaction proceeds via an SN1 mechanism because the formation of a stable carbocation is favored.
- The oxonium ion loses the ethyl group (CH2-CH3) to form a tertiary carbocation:
```
C(CH3)3 - O^+H → C(CH3)3^+ + CH3CH2OH
```

### Step 5: Nucleophilic Attack by Iodide Ion
- The iodide ion (I-) from HI will then attack the tertiary carbocation:
```
C(CH3)3^+ + I- → C(CH3)3I
```

### Step 6: Products of the Reaction
- The final products of the reaction are:
- Tertiary alkyl halide: tert-butyl iodide (C(CH3)3I)
- Ethanol (C2H5OH)

### Conclusion
- Therefore, the reaction of ethyl-tert-butyl ether with HI produces tert-butyl iodide and ethanol.

### Final Answer
- The products formed are tert-butyl iodide and ethanol.

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