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When diethyl ether is treated with exces...

When diethyl ether is treated with excess of `CI_(2)` in the presence of sum light, the product formed is :

A

`CH_(3)CHCI-O-CH_(2)CH_(3)`

B

`CH_(3)CHCI-O-CHCICH_(3)`

C

`C CI_(3)C CI_(2)-O-C CI_(2)C CI_(3)`

D

`CH_(3)C CI_(2)-O-CHCICH_(3)`.

Text Solution

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The correct Answer is:
To solve the question regarding the reaction of diethyl ether with excess chlorine in the presence of sunlight, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reactants**: - The reactant is diethyl ether, which has the chemical formula \( CH_3CH_2OCH_2CH_3 \). - The other reactant is chlorine gas (\( Cl_2 \)). 2. **Understand the Reaction Conditions**: - The reaction takes place in the presence of sunlight, which indicates that this is a photochemical reaction. Sunlight provides the energy needed to initiate the reaction. 3. **Mechanism of Reaction**: - In the presence of sunlight, chlorine can undergo homolytic cleavage, producing chlorine radicals (\( Cl \cdot \)). - These radicals can then abstract hydrogen atoms from diethyl ether, leading to a substitution reaction where hydrogen atoms are replaced by chlorine atoms. 4. **Substitution of Hydrogen Atoms**: - Diethyl ether has a total of 10 hydrogen atoms (from the two ethyl groups). - When treated with excess \( Cl_2 \), all 10 hydrogen atoms can be substituted by chlorine atoms. 5. **Formation of Products**: - The complete substitution of all hydrogen atoms by chlorine results in the formation of a compound with the formula \( C_2Cl_5O \) (since the ether oxygen remains intact). - The final product can be represented as \( CCl_3CH_2OCH_2CCl_3 \) or \( Cl_2C-O-CCl_2CCl_3 \). 6. **By-products**: - Along with the main product, hydrogen chloride (\( HCl \)) is also formed as a by-product due to the substitution of hydrogen atoms. 7. **Final Product Representation**: - The final product can be summarized as: \[ CCl_3CH_2OCH_2CCl_3 + 10 HCl \] 8. **Conclusion**: - Therefore, the product formed when diethyl ether is treated with excess \( Cl_2 \) in the presence of sunlight is a fully chlorinated ether along with hydrogen chloride. ### Answer: The product formed is \( CCl_3CH_2OCH_2CCl_3 \) (fully chlorinated diethyl ether) along with \( HCl \).

To solve the question regarding the reaction of diethyl ether with excess chlorine in the presence of sunlight, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reactants**: - The reactant is diethyl ether, which has the chemical formula \( CH_3CH_2OCH_2CH_3 \). - The other reactant is chlorine gas (\( Cl_2 \)). ...
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