How many isomeric alcohols with formula `C_(4)H_(10)O` are possible ?

Options

A. 3
B. 2
C. 4
D. 5

Explanation

To determine the number of isomeric alcohols with the formula C₄H₁₀O, we will analyze the possible structural variations of alcohols that can be formed with this molecular formula.

### Step-by-Step Solution:

1. **Identify the General Structure of Alcohols**:
- Alcohols have the functional group -OH (hydroxyl group).
- The general formula for alcohols can be represented as R-OH, where R is an alkyl group.

2. **Count the Carbon Atoms**:
- The formula C₄H₁₀O indicates that there are 4 carbon atoms in the alcohol.

3. **Determine Possible Carbon Skeletons**:
- The carbon skeletons can be straight-chain or branched.
- The possible carbon skeletons for 4 carbon atoms are:
- Straight-chain: Butane (n-butanol)
- Branched: Isobutane (2-methylpropane)

4. **Draw Possible Structures**:
- **n-Butanol (Butan-1-ol)**: CH₃-CH₂-CH₂-CH₂OH
- **Isobutanol (2-Methylpropan-1-ol)**: (CH₃)₂CH-CH₂OH
- **Sec-Butanol (Butan-2-ol)**: CH₃-CH(OH)-CH₂-CH₃
- **Tert-Butanol (2-Methylpropan-2-ol)**: (CH₃)₃COH

5. **List the Isomeric Alcohols**:
- From the above structures, we can identify the following isomeric alcohols:
1. n-Butanol (Butan-1-ol)
2. Sec-Butanol (Butan-2-ol)
3. Isobutanol (2-Methylpropan-1-ol)
4. Tert-Butanol (2-Methylpropan-2-ol)

6. **Count the Isomeric Alcohols**:
- After listing, we find a total of **4 isomeric alcohols**.

### Conclusion:
The total number of isomeric alcohols with the formula C₄H₁₀O is **4**.