Formation of methyl tertiary butyl ether by the reaction of sodium tertiary butoxide and methyl bromide involves.

Options

A. elimination reaction
B. electrophilic addition reaction
C. nuclephilic addition reaction
D. muclephilic substitution reaction

Explanation

To determine the type of reaction involved in the formation of methyl tertiary butyl ether from sodium tertiary butoxide and methyl bromide, we can break down the process step by step.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are sodium tertiary butoxide (Na^+ (C(CH3)3O^−)) and methyl bromide (CH3Br).

2. **Understand the Structure of Sodium Tertiary Butoxide**:
- Sodium tertiary butoxide consists of a sodium ion (Na^+) and a tert-butoxide ion (C(CH3)3O^−). The tert-butoxide ion acts as a strong nucleophile due to the presence of the negatively charged oxygen.

3. **Identify the Type of Alkyl Halide**:
- Methyl bromide (CH3Br) is a primary alkyl halide because it has one carbon atom attached to the carbon bonded to the bromine atom.

4. **Recognize the Reaction Mechanism**:
- The reaction between a strong nucleophile (tert-butoxide) and a primary alkyl halide (methyl bromide) typically proceeds via an SN2 mechanism. In this mechanism, the nucleophile attacks the electrophilic carbon atom of the alkyl halide, leading to the displacement of the leaving group (bromide ion, Br^−).

5. **Write the Reaction**:
- The reaction can be represented as follows:
\[ \text{Na}^+ \text{(C(CH}_3)_3\text{O}^-) + \text{CH}_3\text{Br} \rightarrow \text{CH}_3\text{O(C(CH}_3)_3) + \text{NaBr} \]
- This results in the formation of methyl tertiary butyl ether (CH3O(C(CH3)3)) and sodium bromide (NaBr).

6. **Conclusion**:
- The reaction involves nucleophilic substitution, specifically an SN2 reaction, where the tert-butoxide ion acts as a nucleophile and replaces the bromine atom in methyl bromide.

### Final Answer:
The formation of methyl tertiary butyl ether by the reaction of sodium tertiary butoxide and methyl bromide involves a **nucleophilic substitution reaction (SN2)**.

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