Sodium ethoxide has reacted with ethanoyl chloride. The compound that is produced in this reaction is `:`

Options

A. Diethyl ether
B. Butan-2-one
C. Ethyl chloride
D. Ethylethanoate.

Explanation

To solve the problem of what compound is produced when sodium ethoxide reacts with ethanoyl chloride, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- Sodium ethoxide (C2H5ONa) is a strong nucleophile.
- Ethanoyl chloride (CH3COCl) is an acyl chloride.

2. **Nucleophilic Attack**:
- The lone pair of electrons on the oxygen atom of sodium ethoxide attacks the carbon atom of the carbonyl group (C=O) in ethanoyl chloride. This carbon is electrophilic due to the presence of the electronegative chlorine atom.

3. **Formation of Tetrahedral Intermediate**:
- This attack leads to the formation of a tetrahedral intermediate, where the oxygen from sodium ethoxide is now bonded to the carbonyl carbon, and the chlorine atom is still attached to the carbon.

4. **Chlorine Leaving**:
- The tetrahedral intermediate collapses, leading to the elimination of the chloride ion (Cl-). This results in the formation of a carbonyl compound.

5. **Formation of Ethyl Ethanoate**:
- The product formed after the elimination of Cl- is ethyl ethanoate (C2H5COOCH3), which is an ester.

6. **Final Product**:
- The final compound produced from the reaction of sodium ethoxide with ethanoyl chloride is ethyl ethanoate.

### Final Answer:
The compound produced in this reaction is **ethyl ethanoate (C2H5COOCH3)**.

---