Asssertion : 2-iodobutane on reacting with sodium ehtoxide. In ethanol gives but -2-ene as the major prodcut.
Reason : But-2-ene is more stable than but-1-ene.

Options

A. If both assertion and reason are correct and reason is correct explanation for assertion.
B. If both assertion and reason are correct but reason is not correct for assertion.
C. If assertion is correct but reason is incorrect.
D. If both assertion and reason are incorrect.

Explanation

To solve the question, we need to analyze the assertion and the reason provided regarding the reaction of 2-iodobutane with sodium ethoxide in ethanol.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant is 2-iodobutane (C4H9I), which has the structure:
\[ CH_3-CH(I)-CH_2-CH_3 \]
- The other reactant is sodium ethoxide (C2H5ONa).

2. **Understanding the Reaction Type**:
- The reaction between an alkyl halide (2-iodobutane) and sodium ethoxide is a type of nucleophilic substitution reaction. This is often referred to as the Williamson ether synthesis.

3. **Mechanism of the Reaction**:
- In this reaction, the ethoxide ion (C2H5O^-) acts as a nucleophile and attacks the carbon atom bonded to the iodine (the leaving group).
- The iodine leaves as iodide ion (I^-), and an ether is formed.

4. **Formation of Ether**:
- The reaction will produce an ether, specifically ethyl butyl ether:
\[ CH_3-CH(OCH_2CH_3)-CH_2-CH_3 + NaI \]
- This indicates that the assertion stating that but-2-ene is the major product is incorrect.

5. **Stability of Alkenes**:
- The reason states that but-2-ene is more stable than but-1-ene. This is true because but-2-ene is a more substituted alkene compared to but-1-ene, which makes it more stable due to hyperconjugation and the inductive effect.

6. **Conclusion**:
- Therefore, the assertion that 2-iodobutane gives but-2-ene as the major product is incorrect.
- However, the reason that but-2-ene is more stable than but-1-ene is correct.

### Final Answer:
- The assertion is **false**, and the reason is **true**.