`CH_(3)-overset(CH_(3))overset(|)(CH)CH=CHCH_(3)overset(H_(3)O^(+))rarr`
Major product of the reaction

Explanation

To solve the given question regarding the hydrolysis of the alkene, let's break down the steps involved in the reaction:

### Step-by-Step Solution:

1. **Identify the Alkene Structure**:
The given compound is an alkene with the structure:
\[ CH_3-CH(CH_3)-CH=CH-CH_3 \]
This indicates that there is a double bond between the carbon atoms.

2. **Understand Hydrolysis of Alkene**:
When an alkene undergoes hydrolysis in the presence of an acid (H₃O⁺), it undergoes an electrophilic addition reaction. The double bond opens up, and H⁺ from the acid adds to one of the carbon atoms in the double bond, while OH⁻ adds to the other.

3. **Formation of Carbocation**:
The double bond between the carbon atoms will break, leading to the formation of a carbocation. In this case, the proton (H⁺) will add to the carbon that results in the more stable carbocation:
\[ CH_3-CH^+(CH_3)-CH-CH_2-CH_3 \]
Here, we form a secondary carbocation.

4. **Carbocation Rearrangement**:
Secondary carbocations can rearrange to form more stable tertiary carbocations. In this case, a hydride shift occurs, where a hydrogen atom from an adjacent carbon shifts to the positively charged carbon:
\[ CH_3-CH(CH_3)-C^+(CH_3)-CH_2-CH_3 \]
This results in a more stable tertiary carbocation.

5. **Nucleophilic Attack**:
The hydroxide ion (OH⁻) from the acid will then attack the tertiary carbocation:
\[ CH_3-CH(CH_3)-C(OH)(CH_3)-CH_2-CH_3 \]

6. **Final Product**:
The final product of this reaction is a tertiary alcohol:
\[ CH_3-CH(CH_3)-C(OH)(CH_3)-CH_2-CH_3 \]
This compound is the major product of the reaction.

### Conclusion:
The major product of the hydrolysis of the given alkene is a tertiary alcohol.