The end product (C) of the following reaction is :
`CH_(3)COOH overset(CaCO_(3))rarrAoverset("Heat")rarrBoverset(NH_(2)OH)rarr`

Options

A. Acetaldoxmine
B. Formaldoxime
C. Methyl nitrate
D. Acetoxmine

Explanation

To solve the given problem step by step, we will analyze each part of the reaction involving acetic acid and identify the end product (C).

### Step 1: Reaction of Acetic Acid with Calcium Carbonate
The first step involves the reaction of acetic acid (CH₃COOH) with calcium carbonate (CaCO₃).

**Reaction:**
\[ \text{CH}_3\text{COOH} + \text{CaCO}_3 \rightarrow \text{Calcium Acetate} + \text{CO}_2 + \text{H}_2\text{O} \]

**Result:**
The product formed in this step is calcium acetate (CH₃COO)₂Ca, along with carbon dioxide (CO₂) and water (H₂O). This product is denoted as A.

### Step 2: Heating Calcium Acetate
Next, we heat the calcium acetate (A).

**Reaction:**
\[ \text{(CH}_3\text{COO)}_2\text{Ca} \xrightarrow{\text{Heat}} \text{Acetone} + \text{CaCO}_3 \]

**Result:**
Upon heating, calcium acetate decomposes to form acetone (CH₃COCH₃) and calcium carbonate (CaCO₃). This product is denoted as B.

### Step 3: Reaction of Acetone with Hydroxylamine
Now, we react acetone (B) with hydroxylamine (NH₂OH).

**Reaction:**
\[ \text{CH}_3\text{COCH}_3 + \text{NH}_2\text{OH} \rightarrow \text{Acetone Oxime} \]

**Intermediate Formation:**
The reaction first forms an intermediate where the hydroxylamine adds to the carbonyl group of acetone, leading to the formation of a compound with a hydroxyl group and an amine group.

### Step 4: Formation of Acetone Oxime
After the intermediate is formed, a dehydration step occurs where water (H₂O) is eliminated, resulting in the formation of the final product.

**Final Product:**
The final product (C) is acetone oxime (CH₃C(=NOH)CH₃).

### Conclusion
The end product (C) of the reaction sequence is **acetone oxime**.

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