Iodoform can be prepared from all except

Options

A. butan-2-one
B. acetophenone
C. propan-2-ol
D. propan-1-ol

Explanation

To determine which compound cannot produce iodoform, we need to understand the conditions required for the iodoform test. The iodoform test is used to identify methyl ketones (compounds with the structure RCOCH3) and secondary alcohols that can be oxidized to methyl ketones.

### Step-by-Step Solution:

1. **Understand the Iodoform Test**: The iodoform test is specifically for compounds that have the structure CH3CO- (methyl ketones) or secondary alcohols that can be oxidized to this structure. The presence of the methyl group adjacent to a carbonyl group is essential.

2. **Identify the Compounds**: We need to analyze the given options to see which one does not fit the criteria for producing iodoform. The options typically include different types of alcohols and ketones.

3. **Analyze Propan-1-ol**:
- Propan-1-ol (CH3CH2CH2OH) is a primary alcohol.
- It does not have a methyl group adjacent to a carbonyl group.
- When oxidized, it forms propanal (an aldehyde), which cannot be further oxidized to a methyl ketone.

4. **Conclusion**: Since propan-1-ol does not have the necessary structure to yield iodoform, it cannot produce iodoform upon treatment with iodine and a base.

5. **Final Answer**: The compound that cannot produce iodoform is **Propan-1-ol**.