In the following squence of reactions
`"Toluene" overset(KMnO_(4))(to)A`, the product A is

Options

A. `C_(6)H_(5)CH_(2)OH`
B. `C_(6)H_(5)CHO`
C. `C_(6)H_(5)COOH`
D. `C_(6)H_(5)CH_(3)`

Explanation

To determine the product A formed from the oxidation of toluene using KMnO4, we can follow these steps:

### Step-by-Step Solution:

1. **Identify Toluene Structure**:
Toluene is a methyl-substituted benzene, represented as C6H5-CH3. It consists of a benzene ring (C6H5) with a methyl group (CH3) attached.

2. **Understand the Reaction Conditions**:
The reaction involves the use of KMnO4, which is a strong oxidizing agent. This means it will facilitate the oxidation of toluene.

3. **Oxidation of Toluene**:
When toluene is treated with KMnO4, the methyl group (CH3) is oxidized. In this reaction, the methyl group is converted into a carboxylic acid group (COOH).

4. **Determine the Product**:
The oxidation of toluene leads to the formation of benzoic acid. The structure of benzoic acid is C6H5-COOH, where the carboxylic acid group is now attached to the benzene ring.

5. **Conclusion**:
Therefore, the product A formed from the oxidation of toluene with KMnO4 is benzoic acid.

### Final Answer:
The product A is **benzoic acid (C6H5COOH)**.

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