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Give IUPAC name of : Br-CH(2)-CHO...

Give IUPAC name of : `Br-CH_(2)-CHO`

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To find the IUPAC name of the compound `Br-CH₂-CHO`, we can follow these steps: ### Step 1: Identify the longest carbon chain The compound has a total of two carbon atoms. The longest carbon chain consists of these two carbon atoms. ### Step 2: Identify the functional group In this compound, we have an aldehyde functional group (–CHO) at one end of the carbon chain. Aldehydes are characterized by the presence of the carbonyl group (C=O) at the terminal position. ### Step 3: Number the carbon chain We need to number the carbon chain in such a way that the aldehyde group receives the lowest possible number. Therefore, we start numbering from the end of the chain that is closest to the aldehyde group: - The first carbon (C1) is part of the aldehyde group. - The second carbon (C2) is the other carbon in the chain. ### Step 4: Identify and name the substituents At position 2 (C2), there is a bromine (Br) substituent. In IUPAC nomenclature, substituents are named as prefixes. The prefix for bromine is "bromo". ### Step 5: Combine the names Now we can combine the names: - The parent chain is "ethane" (since there are two carbon atoms). - The substituent "bromo" is at position 2. - Since we have an aldehyde, we will use the suffix "al". ### Step 6: Write the final IUPAC name Putting it all together, the IUPAC name of the compound is: **2-bromoethanal**. ### Summary of the IUPAC Name: - The compound is named **2-bromoethanal**. ---

To find the IUPAC name of the compound `Br-CH₂-CHO`, we can follow these steps: ### Step 1: Identify the longest carbon chain The compound has a total of two carbon atoms. The longest carbon chain consists of these two carbon atoms. ### Step 2: Identify the functional group In this compound, we have an aldehyde functional group (–CHO) at one end of the carbon chain. Aldehydes are characterized by the presence of the carbonyl group (C=O) at the terminal position. ...
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