Write structural formula of 3-Bromobenzoic acid.

Explanation

To write the structural formula of 3-Bromobenzoic acid, we will follow these steps:

### Step 1: Draw the Benzene Ring
Start by drawing a hexagonal shape to represent the benzene ring. Benzene is a six-carbon ring with alternating double bonds.

**Hint:** Remember that benzene has a planar structure with six carbon atoms and is represented as a hexagon.

### Step 2: Add the Carboxylic Acid Group
Next, we need to add the carboxylic acid group (-COOH) to one of the carbon atoms in the benzene ring. This group will be attached to one of the carbon atoms in the ring.

**Hint:** The carboxylic acid group consists of a carbon atom double-bonded to an oxygen atom and single-bonded to a hydroxyl group (-OH).

### Step 3: Identify the Position for the Bromine Substituent
Since we are looking for 3-Bromobenzoic acid, we need to place a bromine atom at the meta position relative to the carboxylic acid group. The carboxylic acid group is at position 1, so the bromine will be at position 3.

**Hint:** The positions on the benzene ring are numbered starting from the carbon attached to the carboxylic acid group. Position 1 is where the -COOH is attached.

### Step 4: Draw the Bromine Atom
Now, add the bromine atom (Br) to the benzene ring at the third position. This means it will be two carbons away from the carboxylic acid group.

**Hint:** Make sure to clearly indicate the bromine atom on the benzene ring at the correct position.

### Step 5: Finalize the Structural Formula
The final structure should show the benzene ring, the carboxylic acid group at position 1, and the bromine atom at position 3. The complete structural formula of 3-Bromobenzoic acid can be represented as follows:

```
Br
|
C6H4 - COOH
```

### Summary of the Structural Formula
The structural formula of 3-Bromobenzoic acid consists of a benzene ring with a carboxylic acid group at position 1 and a bromine atom at position 3.