Which of the following esters is formed by reacting propan-2-ol with ethanoic acid ?

Options

A. `(CH_(3))_(2)CHCOOCH_(3)`
B. `CH_(3)COOCH_(2)CH_(3)`
C. `CH_(3)COOCH(CH_(3))_(2)`
D. `(CH_(3))_(2)CHCOOCH_(2)CH_(3)`

Explanation

To determine which ester is formed by reacting propan-2-ol with ethanoic acid, we can follow these steps:

### Step 1: Identify the reactants
We have two reactants:
- Propan-2-ol (also known as isopropyl alcohol) with the structure:
\[ \text{CH}_3\text{C(OH)}\text{CH}_3 \]
- Ethanoic acid (also known as acetic acid) with the structure:
\[ \text{CH}_3\text{COOH} \]

### Step 2: Understand the esterification reaction
Esterification is a reaction between an alcohol and a carboxylic acid, resulting in the formation of an ester and water. The general reaction can be represented as:
\[ \text{Alcohol} + \text{Carboxylic Acid} \rightarrow \text{Ester} + \text{Water} \]

### Step 3: Combine the reactants
In this case, propan-2-ol will react with ethanoic acid. The hydroxyl group (-OH) from the acid and a hydrogen atom from the alcohol will combine to form water (H2O), and the remaining parts will form the ester.

### Step 4: Determine the structure of the ester
The ester formed will have the structure:
- The alkyl part from propan-2-ol: \(\text{CH}_3\text{C(=O)}\text{CH}_3\)
- The acyl part from ethanoic acid: \(\text{CH}_3\text{COO}\)

Thus, the structure of the ester will be:
\[ \text{CH}_3\text{C(=O)}\text{O}\text{CH(CH}_3\text{)}_2 \]
This compound is known as isopropyl acetate.

### Step 5: Identify the correct option
Based on the structure derived, the correct ester formed from the reaction of propan-2-ol and ethanoic acid is isopropyl acetate.

### Conclusion
The correct answer is **isopropyl acetate**.

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