A compound [A] has the formula `C_(4)H_(8)O_(2)`. When reacted with a Grignard reagent, `CH_(3)MgBr`, it takes up two molecules of it and upon acidification gives an alcohol [B]. The alcohol on reacting with Lucas reagent gives white coludiness on standing for sometime. When the alochol is oxidised, a compound [C] is produced with a pleasant smell. It neither reacts with Tollen's reagent, nor with Fehling's reagent.
The compound [A] is

Options

A. n-propyl formate
B. ethylacetate
C. methylpropionate
D. None of these.

Explanation

To determine the compound [A] with the formula \( C_4H_8O_2 \), we can follow these steps:

### Step 1: Analyze the Molecular Formula
The molecular formula \( C_4H_8O_2 \) suggests that the compound could be an ester or a carboxylic acid.

### Step 2: Reaction with Grignard Reagent
The compound reacts with the Grignard reagent \( CH_3MgBr \) and takes up two molecules of it. This indicates that the compound is likely an ester, as esters typically react with Grignard reagents to form alcohols.

### Step 3: Identify the Structure of Compound [A]
Given that the compound takes up two molecules of the Grignard reagent, we can deduce that it is likely a simple ester. The structure can be represented as:
- An ester formed from formic acid and an alcohol.

A possible structure for compound [A] is:
\[ CH_3OCOCH_2CH_3 \]
This is N-propyl formate.

### Step 4: Formation of Alcohol [B]
Upon acidification, the ester reacts to form a secondary alcohol [B]. The reaction can be summarized as:
\[ RCOOR' + 2 CH_3MgBr \rightarrow RCH(OH)R' + MgBr(OR') \]

### Step 5: Reaction with Lucas Reagent
The alcohol [B] gives white cloudiness when reacted with Lucas reagent, indicating that it is a secondary alcohol. This is consistent with the expected product from the reaction of the Grignard reagent with the ester.

### Step 6: Oxidation of Alcohol [B]
When the alcohol [B] is oxidized, it produces compound [C], which has a pleasant smell. This suggests that compound [C] is likely an ester or a ketone.

### Step 7: Reactivity with Tollen's and Fehling's Reagents
The compound [C] does not react with Tollen's reagent or Fehling's reagent, indicating that it is not an aldehyde or a reducing sugar. This further supports the idea that [C] is likely an ester or a ketone.

### Conclusion
Based on the analysis, the compound [A] is identified as:
**N-propyl formate (CH3OCOCH2CH3)**.