`underset("Ester"(A))(C_(4)H_(8)O_(2))+CH_(3)underset((2"parts"))(MgBr)overset(H_(3)O^(+))rarrunderset("Aalcohol"(B))(C_(4)H_(10)O)`
The alcohol (B) reacts fastest with Luces reaent. The ester (A) and alcohol (B) are :

Options

A. `CH_(3)COOC_(2)H_(5)" and "(CH_(3))_(3)COH`
B. `HCOOC_(3)H_(7)" and "(CH_(3))_(2)CHOH`
C. `C_(2)H_(5)COOCH_(3)" and "(C_(2)H_(5))_(3)COH`
D. `HCOOC_(3)H_(7)" and "(CH_(3))_(3)COH.`

Answer

A

Explanation

(a) The alcohol is a tertiary alcohol `(CH_(3))_(3)COH` since it reacts fastest with Lucas reagent. `CH_(3)COOC_(2)H_(5)` will form this alcohol. Ester `HCOOC_(3)H_(7)`(d) will not form teritary alcohol. It will give secondary alcohol.