Give IUPAC name of `Br-CH_(2)-CH_(2)-CH_(2)-OH`.

Explanation

To determine the IUPAC name of the compound `Br-CH₂-CH₂-CH₂-OH`, we will follow these steps:

### Step 1: Identify the Longest Carbon Chain
The first step in naming a compound is to identify the longest continuous carbon chain. In this case, the longest chain consists of three carbon atoms (C-C-C).

### Step 2: Identify the Functional Groups
Next, we need to identify the functional groups present in the compound. Here, we have:
- A hydroxyl group (-OH), which is an alcohol.
- A bromine atom (Br), which is a halogen substituent.

### Step 3: Determine the Priority of Functional Groups
According to IUPAC nomenclature rules, the hydroxyl group (-OH) has a higher priority than the bromine substituent. Therefore, we will number the carbon chain starting from the end closest to the hydroxyl group.

### Step 4: Number the Carbon Chain
We will number the carbon chain from the end where the hydroxyl group is attached:
- The carbon with the -OH group is carbon 1.
- The second carbon is carbon 2.
- The third carbon is carbon 3.

### Step 5: Identify the Positions of the Substituents
Now, we can identify the positions of the substituents:
- The hydroxyl group is at position 1 (1-ol).
- The bromine substituent is at position 3 (3-bromo).

### Step 6: Combine the Information to Form the IUPAC Name
Now we can combine the information:
- The base name for a three-carbon chain is "propane".
- Since the hydroxyl group is at position 1, we will use "propane-1-ol".
- The bromine substituent at position 3 will be prefixed as "3-bromo".

Putting it all together, the IUPAC name of the compound is:
**3-bromo-1-propanol**.

### Final Answer:
**3-bromo-1-propanol**

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