The size of the nucleus is approximately

Options

A. 1/100th of atom
B. 1/1000th of the atom
C. 1/10000th of the atom
D. 1/100000th of the atom

Explanation

To determine the size of the nucleus in relation to the size of an atom, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Sizes**:
- The size of a nucleus is approximately \(10^{-13}\) meters.
- The size of an atom is approximately \(10^{-8}\) meters.

2. **Set Up the Ratio**:
- We want to find the ratio of the size of the nucleus to the size of the atom:
\[ \text{Ratio} = \frac{\text{Size of nucleus}}{\text{Size of atom}} = \frac{10^{-13}}{10^{-8}} \]

3. **Simplify the Expression**:
- When dividing powers of ten, we subtract the exponents:
\[ \frac{10^{-13}}{10^{-8}} = 10^{-13 - (-8)} = 10^{-13 + 8} = 10^{-5} \]

4. **Interpret the Result**:
- The result \(10^{-5}\) can be expressed as:
\[ 10^{-5} = \frac{1}{10^5} \]
- This means that the size of the nucleus is \(1\) divided by \(10^5\) times the size of the atom.

5. **Conclusion**:
- Therefore, the size of the nucleus is approximately \( \frac{1}{10^5} \) times the size of the atom.

### Final Answer:
The size of the nucleus is approximately \( \frac{1}{10^5} \) times the size of the atom.

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