Home
Class 11
CHEMISTRY
A metallic ion M^(2+) has an electron co...

A metallic ion `M^(2+)` has an electron configuration of 2,8,14 and its mass is 56 amu. The number of neutrons in the nucleus is

A

32

B

42

C

30

D

34

Text Solution

Verified by Experts

The correct Answer is:
C
The electrons in dipositive ion `(M^(12+))` is 2+8 +14 =24, Electrons = Protons in M = 26
`:.` Neutrons `= 56 -26 = 30`.
Promotional Banner

Similar Questions

Explore conceptually related problems

The electronic configuration of Ti^(2+) ion is ………….

What is the electronic configuration of O^(2-) ion?

An atom has 26 electrons and its atomic weight is 56. The number of neutrons in the nucleus of the atom will be

The electronic configuration of a dipositive ion M^(2+) is 2, 8, 14 and its mass number is 56. The number of netrons present is

the correct electronic configuration of Cu^(2+) ion is

The electronic configuration of a dipositive ion M2+ is 2,8,14 and its mass number is 56. What is the number of neutrons present?

An element 'X' has its electronic configuration of 'K' shell is (n-5)s^(2) and it has total number of electrons in its outermost, penultimate and antipenultimate shell are 2,8 and 25 respectively then find out total number of unpaired electrons in element 'X' in their ground state.

The electronic configuration of Re^(3+) is (Xe)4f^(14)5d^(4) , the number of unpaired electrons in this ion is ____________.

An element has electronic configuration 2,8,7 What is the valency of this element.

The electronic configuration of an ion M^(2+) is 1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(6) and the atomic weight of M is 56. The number of neutrons in the nucleus of M^(2+) is