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The mass of one mole of electron is...

The mass of one mole of electron is

A

`9.1 xx 10^(-28) g`

B

`0.55 mg`

C

`9.1 xx 10^(-24)g`

D

`1.008 mg`

Text Solution

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The correct Answer is:
To find the mass of one mole of electrons, we can follow these steps: ### Step 1: Identify the mass of a single electron The mass of one electron is given as: \[ m_e = 9.1 \times 10^{-31} \text{ kg} \] ### Step 2: Convert the mass of the electron to grams Since we need the mass in grams, we convert kilograms to grams using the conversion factor \(1 \text{ kg} = 1000 \text{ g}\): \[ m_e = 9.1 \times 10^{-31} \text{ kg} \times 1000 \text{ g/kg} = 9.1 \times 10^{-28} \text{ g} \] ### Step 3: Use Avogadro's number to find the mass of one mole of electrons Avogadro's number (\(N_A\)) is: \[ N_A = 6.022 \times 10^{23} \text{ particles/mole} \] To find the mass of one mole of electrons, we multiply the mass of a single electron by Avogadro's number: \[ \text{Mass of 1 mole of electrons} = m_e \times N_A \] \[ = (9.1 \times 10^{-28} \text{ g}) \times (6.022 \times 10^{23}) \] ### Step 4: Perform the multiplication Calculating the product: \[ = 9.1 \times 6.022 \times 10^{-28 + 23} \] \[ = 54.78 \times 10^{-5} \text{ g} \] ### Step 5: Convert the mass to milligrams To convert grams to milligrams, we use the conversion \(1 \text{ g} = 1000 \text{ mg}\): \[ 54.78 \times 10^{-5} \text{ g} = 54.78 \times 10^{-2} \text{ mg} = 0.5478 \text{ mg} \] ### Step 6: Round off the answer Rounding off to two decimal places, we get: \[ \approx 0.55 \text{ mg} \] ### Final Answer: The mass of one mole of electrons is approximately \(0.55 \text{ mg}\). ---

To find the mass of one mole of electrons, we can follow these steps: ### Step 1: Identify the mass of a single electron The mass of one electron is given as: \[ m_e = 9.1 \times 10^{-31} \text{ kg} \] ...
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