Home
Class 11
CHEMISTRY
For a certain particle, it is found that...

For a certain particle, it is found that uncertainty in velocity is reciprocal of uncertainty in position. This implies that

A

Mass of the particle is `gt` unity

B

Mass of the particle is unity

C

Mass of the particle `le` h

D

Mass of the particle `ge h//4 pi`.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the relationship between the uncertainties in velocity and position as given in the question. ### Step-by-Step Solution: 1. **Understanding the Given Information**: We are given that the uncertainty in velocity (Δv) is the reciprocal of the uncertainty in position (Δx). Mathematically, this can be expressed as: \[ \Delta v \propto \frac{1}{\Delta x} \] This implies: \[ \Delta v \cdot \Delta x = k \] where \( k \) is a constant. 2. **Applying Heisenberg's Uncertainty Principle**: According to Heisenberg's Uncertainty Principle, the product of the uncertainties in position and momentum is given by: \[ \Delta x \cdot \Delta p \geq \frac{h}{4\pi} \] where \( \Delta p \) is the uncertainty in momentum and \( h \) is Planck's constant. 3. **Relating Momentum to Mass and Velocity**: The uncertainty in momentum (Δp) can be expressed as: \[ \Delta p = m \cdot \Delta v \] where \( m \) is the mass of the particle. 4. **Substituting into the Uncertainty Principle**: Now substituting \( \Delta p \) into the uncertainty principle: \[ \Delta x \cdot (m \cdot \Delta v) \geq \frac{h}{4\pi} \] From our earlier relationship, we have \( \Delta v = \frac{k}{\Delta x} \). Substituting this into the equation gives: \[ \Delta x \cdot \left(m \cdot \frac{k}{\Delta x}\right) \geq \frac{h}{4\pi} \] Simplifying this, we get: \[ m \cdot k \geq \frac{h}{4\pi} \] 5. **Finding the Condition on Mass**: Rearranging the inequality gives: \[ m \geq \frac{h}{4\pi k} \] Since \( k \) is a constant, we can denote it as \( k = 1 \) for simplicity, which leads to: \[ m \geq \frac{h}{4\pi} \] 6. **Conclusion**: From the above derivation, we conclude that the mass of the particle must be greater than \( \frac{h}{4\pi} \). Thus, the correct answer is: - The mass of the particle is greater than \( \frac{h}{4\pi} \). ### Final Answer: The mass of the particle is greater than \( \frac{h}{4\pi} \).

To solve the problem, we need to analyze the relationship between the uncertainties in velocity and position as given in the question. ### Step-by-Step Solution: 1. **Understanding the Given Information**: We are given that the uncertainty in velocity (Δv) is the reciprocal of the uncertainty in position (Δx). Mathematically, this can be expressed as: \[ \Delta v \propto \frac{1}{\Delta x} ...
Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate the uncertainty in the velocity of an electron, if the uncertainity in position is 100 pm.

Using Heisenberg's uncertainty principle, calculate the uncertainty in velocity of an electron if uncertainty in its position is 10^(-11)m Given, h =6.6 xx 10^(-14)kg m^2s^(-1), m=9.1 xx 10^(-31)kg

What will be the uncertainty in velocity of an electron when the uncertainty in its position is 1000 Å?

Calculate the uncertainty in the velocity of an electron of the uncertainty in its position is of the order of 1 Å

Calculate the uncertainty in the velocity of an electron if the uncertainty in its position is of the order of 1 Å

If uncertainty in position and velocity are equal the uncertainty in momentum will be

Calculate the uncertainty in the velocity of a cricket hall (mass = 0.15 kg) uncertainty in position is of the order of 1Å

Calculate the uncertainty in the velocity of a cricket hall (mass = 0.15 kg) uncertainty in position is of the order of 1Å

If uncertainty in position and momentum are equal then uncertainty in velocity is.

Calculate the uncertainty in the velocity of anelectron when the uncertainty in its positionis 1.012 xx 10^(-12) m