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Azimuthal quantum number of last electro...

Azimuthal quantum number of last electron of `._(11)Na` is

A

1

B

2

C

3

D

0

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The correct Answer is:
To determine the azimuthal quantum number of the last electron in sodium (Na), we can follow these steps: ### Step 1: Identify the Atomic Number The atomic number of sodium (Na) is 11. This means that sodium has 11 electrons. ### Step 2: Write the Electron Configuration To find the azimuthal quantum number of the last electron, we need to write the electron configuration of sodium. The electron configuration for sodium is: - 1s² 2s² 2p⁶ 3s¹ ### Step 3: Identify the Last Electron From the electron configuration, we can see that the last electron is in the 3s subshell. ### Step 4: Determine the Principal Quantum Number (n) The principal quantum number (n) for the last electron in the 3s subshell is 3. ### Step 5: Determine the Azimuthal Quantum Number (l) The azimuthal quantum number (l) is determined by the type of subshell: - For s subshells, l = 0 - For p subshells, l = 1 - For d subshells, l = 2 Since the last electron of sodium is in the 3s subshell, we have: - l = 0 ### Conclusion The azimuthal quantum number of the last electron of sodium (Na) is **0**. ---

To determine the azimuthal quantum number of the last electron in sodium (Na), we can follow these steps: ### Step 1: Identify the Atomic Number The atomic number of sodium (Na) is 11. This means that sodium has 11 electrons. ### Step 2: Write the Electron Configuration To find the azimuthal quantum number of the last electron, we need to write the electron configuration of sodium. The electron configuration for sodium is: - 1s² 2s² 2p⁶ 3s¹ ...
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