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The four quantum numbers of vaience ...

The four quantum numbers of vaience electron of potassium are

A

`4,1,1,1//2`

B

`4,0,0,1//2`

C

`4,1,0,1//2`

D

`4,4,0,1//2`

Text Solution

Verified by Experts

The correct Answer is:
B
The electronic configuration of K (Z =19) is `1s^(2)2s^(2)2p^(6)3s^(2) 3p^(6) 4s^(1)`. The last electron is in 4s.
`:. n = 4, l = 0, m_(s) = +(1)/(2)`
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