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If the wavelength of photon is 2.2 xx10...

If the wavelength of photon is `2.2 xx10^(11)` m then the momentum of the photon is

A

`3 xx 10^(-23) kg m s^(-1)`

B

`3.33xx 10^(2) kg m s^(-1)`

C

`1.452 xx 10^(-44) kg ms^(-1)`

D

`6.89 xx 10^(43) kg m s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
Wavelength of a photon `= 2.2 xx 10^(-11)m`
Planck's constant (h) `= 6.6 xx 10^(-34) J s`
According to de-Broglie relation
`lambda = (h)/(p)` or `p = (h)/(lambda)`
where, `lambda`= wavelength, p = momentum
`:. P = (h)/(p) = (6.6 xx 10^(-34))/(2.2 xx 10^(-11)) = 3 xx 10^(-23)`
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