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The energy of a photon is given as 3.03x...

The energy of a photon is given as `3.03xx10^(-19)J`. The wavelength of the photon is

A

`65.6 nm`

B

`656 nm`

C

`0.656 nm`

D

`6.56 nm`

Text Solution

Verified by Experts

The correct Answer is:
B
`Delta E =(hc)/(lambda)` or `lambda =(hc)/(Delta E)`
`= (6.62 xx 10^(-34) xx 3 xx 10^(8))/(3.08 xx 10^(-19)) = 656 nm`.
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