The angular momentum of electron in nth orbit is given by

Options

A. `(2pi)/(nh)`
B. `(pi)/(2nh)`
C. `(nh)/(2pi)`
D. nh

Explanation

To find the angular momentum of an electron in the nth orbit according to Bohr's model, we can follow these steps:

### Step-by-Step Solution:

1. **Understand Bohr's Postulate**: According to Bohr's second postulate, the angular momentum (L) of an electron in a stable orbit is quantized. This means it can only take on certain discrete values.

2. **Formula for Angular Momentum**: The angular momentum of the electron is given by the formula:
\[ L = mvr \]
where:
- \( L \) is the angular momentum,
- \( m \) is the mass of the electron,
- \( v \) is the velocity of the electron,
- \( r \) is the radius of the orbit.

3. **Quantization of Angular Momentum**: According to Bohr's model, the angular momentum is quantized and can be expressed as:
\[ L = n \frac{h}{2\pi} \]
where:
- \( n \) is a positive integer (1, 2, 3,...),
- \( h \) is Planck's constant, approximately \( 6.626 \times 10^{-34} \, \text{Js} \).

4. **Conclusion**: Therefore, the angular momentum of an electron in the nth orbit is given by:
\[ L = n \frac{h}{2\pi} \]

### Final Answer:
The angular momentum of the electron in the nth orbit is given by:
\[ L = n \frac{h}{2\pi} \]