The atomic number of an element is 35. What is the toal number of electrons present in all the p-orbitals of the ground state atom of that element?

Options

A. 6
B. 11
C. 17
D. 23

Explanation

To find the total number of electrons present in all the p-orbitals of the ground state atom of the element with atomic number 35, follow these steps:

### Step 1: Determine the Electronic Configuration
The atomic number of the element is 35, which means it has 35 electrons in its neutral state. We need to write the electronic configuration for these electrons.

1. Fill the orbitals in the order of increasing energy levels:
- 1s: 2 electrons
- 2s: 2 electrons
- 2p: 6 electrons
- 3s: 2 electrons
- 3p: 6 electrons
- 4s: 2 electrons
- 3d: 10 electrons
- 4p: 5 electrons

The complete electronic configuration for the element with atomic number 35 is:
\[ 1s^2 \, 2s^2 \, 2p^6 \, 3s^2 \, 3p^6 \, 4s^2 \, 3d^{10} \, 4p^5 \]

### Step 2: Identify the p-Orbitals
Now, we need to identify the p-orbitals in this configuration. The p-orbitals are located in the following energy levels:
- 2p: 6 electrons
- 3p: 6 electrons
- 4p: 5 electrons

### Step 3: Count the Electrons in the p-Orbitals
Now, we will sum the electrons in all the p-orbitals:
- Electrons in 2p = 6
- Electrons in 3p = 6
- Electrons in 4p = 5

Total number of electrons in p-orbitals:
\[ 6 + 6 + 5 = 17 \]

### Step 4: Conclusion
The total number of electrons present in all the p-orbitals of the ground state atom of the element with atomic number 35 is **17**.

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