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Time taken for an electron to complete o...

Time taken for an electron to complete one revolution in Bohr orbit of hydrogen atom is

A

`(4pi^(2) mr^(2))/(nh)`

B

`(nh)/(4pi^(2) mr)`

C

`(2pi mr)/(pi^(2) h^(2))`

D

`(h)/(2pi mr)`

Text Solution

Verified by Experts

The correct Answer is:
A
Time taken to complete one revolution.
`t = ("Circumference")/("Velocity")`
`t = (2pi r)/(v)`
Now `m v r = (nh)/(2pi)`
`:. v = (nh)/(2pi mr)`
Substituting the value of v, we get
`t = (2pi r. 2pi m r)/(nh) =(4pi^(2) m r^(2))/(nh)`
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