Effective magentic moment of `Sc^(3+)` ion is

Options

A. `1.73`
B. 0
C. `5.92`
D. `2.83`

Explanation

To find the effective magnetic moment of the `Sc^(3+)` ion, we can follow these steps:

### Step 1: Determine the electronic configuration of Scandium (Sc)
- The atomic number of Scandium (Sc) is 21. Its ground state electronic configuration is:
- `Sc: [Ar] 4s² 3d¹`

### Step 2: Determine the electronic configuration of Scandium in the +3 oxidation state
- In the +3 oxidation state, Scandium loses three electrons. The electrons are removed first from the 4s subshell and then from the 3d subshell:
- Removing 2 electrons from 4s and 1 electron from 3d gives:
- `Sc^(3+): [Ar] 4s⁰ 3d⁰`

### Step 3: Identify the number of unpaired electrons
- In the `Sc^(3+)` ion, the configuration is `4s⁰ 3d⁰`. This means there are no electrons in the 4s or 3d subshells:
- Number of unpaired electrons (n) = 0

### Step 4: Use the formula for effective magnetic moment
- The formula for the effective magnetic moment (μ) is given by:
- \[ \mu = \sqrt{n(n + 2)} \]
- Substituting the value of n:
- \[ \mu = \sqrt{0(0 + 2)} = \sqrt{0} = 0 \]

### Conclusion
- The effective magnetic moment of `Sc^(3+)` ion is **0 Bohr magnetons**.

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