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The wave number of the spectral line in ...

The wave number of the spectral line in the emission spectrum of hydrogen will be equal to 8/9 times the rydbergy's constant if the electron jumps from

A

n = 3 to n = 1

B

n = 10 to n = 1

C

n = 9 to n = 1

D

n = 2 to n = 1

Text Solution

Verified by Experts

The correct Answer is:
A
`bar(v) =R_(H)[(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]` For `n_(1) = 1` and `n_(2) = 3`
`bar(v) = R_(H) [(1)/(1^(2))-(1)/(3^(2))] = R_(H) xx 8//9`
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