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The energies E1 and E2 of two radiations...

The energies `E_1 and E_2` of two radiations are 25 eV and 50 eV respectively. The relation between their wavelengths, i.e., `lambda_(1) and lambda_(2)` will be

A

`lambda_(1) = (1)/(2) lambda_(2)`

B

`lambda_(1) = lambda_(2)`

C

`lambda_(1) = 2lambda_(2)`

D

`lambda_(1) = 4lambda_(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`E = hv =h(c )/(lambda) :. (E_(1))/(E_(2)) = (lambda_(2))/(lambda_(1))`
i.e., `(lambda_(1))/(lambda_(2)) = (E_(2))/(E_(1)) =(50 eV)/(25 eV) = 2 :. lambda_(1) = 2 lambda_(2)`
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