According to the Bohr Theory , which of the hydrogen atom will give rise to the least energetic photon ?

Options

A. n = 6 to n = 1
B. n = 5 to n = 4
C. n = 6 to n = 5
D. n = 5 to n = 3

Answer

C

Explanation

`Delta E = 13.6 ((1)/(n_(1)^(2))-(1)/(n_(2)^(2))) Z^(2)eV`
`(1)/(1^(2))-(1)/(6^(2)) = 1 - (1)/(36) =(35)/(36)`,
`(1)/(4^(2))-(1)/(5^(2)) = (1)/(16) - (1)/(25) = (9)/(400)`
`(1)/(3^(2))-(1)/(5^(2)) = (1)/(9) - (1)/(25) = (16)/(225)`
`Delta E` will be minimum for the transition n = 6 to n = 5