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The ionisation energy of H atom is 13.6...

The ionisation energy of H atom is `13.6 eV` The inoisation energy of `Li^(2+)` law will be

A

`27.2 eV`

B

`40.8 eV`

C

`54.4 eV`

D

`108.8 eV`

Text Solution

Verified by Experts

The correct Answer is:
C
Second ionisation of He is represented as `He^(+) +` energy `rarr He^(2+) +e^(-)`
For hydrogen like particles like `He^(+)`
`IE = E_(H) xx 2^(2) = 13.6 xx 4 =54.4 eV`
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