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The correct arragement of O,P and N in o...

The correct arragement of O,P and N in order of increasing radii is

A

`O lt N lt P`

B

`PltOltN`

C

`OltPltN`

D

`NltOltP`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the correct arrangement of oxygen (O), phosphorus (P), and nitrogen (N) in order of increasing atomic radii, we can follow these steps: ### Step 1: Identify the Group and Period of Each Element - **Nitrogen (N)** is in Group 15 and Period 2. - **Oxygen (O)** is in Group 16 and Period 2. - **Phosphorus (P)** is in Group 15 and Period 3. ### Step 2: Understand the Trend in Atomic Radii - Atomic radii generally **decrease** from left to right across a period due to the increase in effective nuclear charge (Z effective), which pulls the electrons closer to the nucleus. - Atomic radii generally **increase** from top to bottom in a group because additional electron shells are added, making the atom larger. ### Step 3: Compare the Elements - **Oxygen (O)** and **Nitrogen (N)** are in the same period (Period 2). Since oxygen is to the right of nitrogen in the periodic table, it will have a smaller atomic radius than nitrogen. - **Phosphorus (P)** is in Period 3 and is below nitrogen in Group 15. Therefore, phosphorus will have a larger atomic radius than nitrogen due to the addition of a new electron shell. - Since phosphorus is also below oxygen in Group 16, it will have a larger atomic radius than oxygen as well. ### Step 4: Arrange the Elements in Order of Increasing Atomic Radii Based on the trends: - Oxygen (smallest radius) - Nitrogen (medium radius) - Phosphorus (largest radius) Thus, the order of increasing atomic radii is: **O < N < P** ### Final Answer The correct arrangement of O, P, and N in order of increasing radii is: **Oxygen < Nitrogen < Phosphorus** (O < N < P) ---
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