An element X has IE and EA respectively 275 and 1450 kJ `mol^(-1)`. The electronegativity of element according to Pauling scale is

Options

A. 240
B. 250
C. 308
D. 402

Explanation

To find the electronegativity of element X using its ionization energy (IE) and electron affinity (EA), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Ionization Energy (IE) = 275 kJ/mol
- Electron Affinity (EA) = 1450 kJ/mol

2. **Use the Electronegativity Formula:**
The formula to calculate electronegativity (χ) according to the Pauling scale is:
\[ \chi = \frac{IE + EA}{5.6} \]

3. **Substitute the Values into the Formula:**
\[ \chi = \frac{275 + 1450}{5.6} \]

4. **Calculate the Sum of IE and EA:**
\[ 275 + 1450 = 1725 \]

5. **Divide by 5.6:**
\[ \chi = \frac{1725}{5.6} \approx 308.04 \]

6. **Final Result:**
The electronegativity of element X is approximately 308.04.

### Conclusion:
The electronegativity of element X according to the Pauling scale is approximately 308.

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