Among `O,C,F,Cl` and Br the increasing order of atomic radii is

Options

A. F O C Cl Br
B. F C O Cl Br
C. F Cl Br O C
D. C O F Cl Br

Answer

To determine the increasing order of atomic radii among the elements O (Oxygen), C (Carbon), F (Fluorine), Cl (Chlorine), and Br (Bromine), we can follow these steps:

### Step 1: Understand the Periodic Trends
- Atomic radius generally decreases as you move from left to right across a period due to an increase in effective nuclear charge, which pulls the electrons closer to the nucleus.
- Atomic radius increases as you move down a group because additional electron shells are added, which outweighs the increase in nuclear charge.

### Step 2: Identify the Position of Each Element
- **Oxygen (O)**: Group 16, Period 2
- **Carbon (C)**: Group 14, Period 2
- **Fluorine (F)**: Group 17, Period 2
- **Chlorine (Cl)**: Group 17, Period 3
- **Bromine (Br)**: Group 17, Period 4

### Step 3: Compare the Elements
- **Fluorine (F)** is the smallest because it is in the same period as C and O but further to the right.
- **Oxygen (O)** is smaller than Carbon (C) because it is further to the right in the same period.
- **Carbon (C)** is larger than both O and F but smaller than Cl and Br.
- **Chlorine (Cl)** is larger than F and O but smaller than Br.
- **Bromine (Br)** is the largest as it is in the fourth period.

### Step 4: Arrange in Increasing Order
Based on the above comparisons, we can arrange the elements in increasing order of atomic radii:
1. Fluorine (F) - smallest
2. Oxygen (O)
3. Carbon (C)
4. Chlorine (Cl)
5. Bromine (Br) - largest

Thus, the increasing order of atomic radii is:
**F < O < C < Cl < Br**

### Final Answer
**F < O < C < Cl < Br**

---