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The average free path at 1 atm pressure ...

The average free path at `1 atm` pressure is `L`. What should be its value at `5 atm` pressure?

A

`5 l`

B

`(2)/(3) l`

C

`(l)/(5)`

D

unpredictable

Text Solution

Verified by Experts

The correct Answer is:
C
Mean free path, `l = (1)/(sqrt2 pi sigma^(2) (N//V))`
or `l prop (1)/(P) .: N//V prop P " or " prop (1)/(T)`
`(l_(1))/(l_(2)) = 5 " or " l_(2) = (l_(1))/(5)`
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