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At high pressures, the van der Waal's eq...

At high pressures, the van der Waal's equation reduces to

A

`PV = RT`

B

`PV = RT - a//V`

C

`PV = RT + Pb`

D

`PV = RT - a//V^(2)`

Text Solution

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The correct Answer is:
C
At high pressure, the pressure correction for 1 mole of gas is negligible
`:. (a)/(V^(2)) = 0`. However the volume correction cannot be neglected.
`:.` van der Waal's equation reduces to
`(P + 0) (V - b) = RT`.....for 1 mole
or `PV = RT + Pb`
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