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A gaseous mixture contains three gases A...

A gaseous mixture contains three gases A,B and C with a total number of moles of 10 and total pressure of 10 atm. The partial pressure of A and B are 3 atm and 1 atm respectively. If C has molecular weight of 2 g/mol. then, the weight of C present in the mixture will be :

A

6

B

3

C

12

D

8

Text Solution

Verified by Experts

The correct Answer is:
C
Total pressure of mixture of gases A, B and C = 10 atm
Number of total moles = 10
Partial pressure of `A = ("No. of moles of A")/(10) xx 10`
`:. 3 =` No. of moles of A.
`.:` Partical pressure of `B = ("No. of moles of B")/(10) xx 10`
= No. of moles of B.
`:.` No. of moles of `C = 10 - (3+1) = 6`
Now 1 moles of `C = 2g`
`:.` 6 mol of `C = 2 xx 6= 12 g`
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